Mole ConceptHard
Question
Iodobenzene is prepared from aniline (C6H5NH2) in a two-step process as shown here.
C6H5NH2+HNO2+HCl?C6H5N2Cl+2H2O
C6H5N2Cl+KI? C6H5I+N2+KCl
In an actual preparation, 9.30 g of aniline was converted to 16.32 g of iodobenzene. The percentage yield of iodobenzene is (I = 127)
Options
A.8%
B.50%
C.75%
D.80%
Solution
Theoretical yield of C6H5I =
Hence, the percentage yield =
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