Mole ConceptMedium
Question
Iodobenzene is prepared from aniline (C6H5NH2) in a two-step process as shown here.
C6H5NH2+HNO2+HCl?C6H5N2Cl+2H2O
C6H5N2Cl+KI? C6H5I+N2+KCl
In an actual preparation, 9.30 g of aniline was converted to 16.32 g of iodobenzene. The percentage yield of iodobenzene is (I = 127)
Options
A.8%
B.50%
C.75%
D.80%
Solution
Theoretical yield of C6H5I =
Hence, the percentage yield =
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
Two elements A and B combine to form compound X and Y. For the fixed mass of A, masses of B combined for the compounds X...When a sample of hydrogen fluoride is cooled to 303 K, most of the molecules undergo dimerization. If the vapour density...Elevation in boiling point of an aq. solution of urea is 0.52 (Kb for water = 0.52K molality-1). The mole fraction of ur...The percentage of Fe(III) present in iron ore Fe0.93 O1.00 is (Fe = 56)...CH3-CO-CH3(g) ⇋ CH3-CH3 (g) + CO(g)Initial pressure of CH3COCH3 is 100 mm. When equilibrium is set up mole fractio...