Mole ConceptMedium
Question
The minimum mass of sulphuric acid needed for dissolving 3 g of magnesium carbonate is
Options
A.3.5 g
B.7.0 g
C.1.7 g
D.17.0 g
Solution
MgCO3 + H2SO4 → MgSO4 + CO2 + H2O
84 g 98 g
$\therefore 3.0g \frac{98}{84} \times 3 = 3.5g$
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
A quantity of 2.0 g of a triatomic gaseous element was found to occupy a volume of 448 ml at 76 cm of Hg and 273 K. The ...In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass )....Two elements A and B combine to form compound X and Y. For the fixed mass of A, masses of B combined for the compounds X...A mixture of 2 × 1021 molecules of P and 3 × 1021 molecules of Q weighs 0.60 g. If the molecular mass of P is 45, then t...To neutralize completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3PO3), the volume of 0.1 M aqueous KOH so...