Chemical Kinetics and Nuclear ChemistryHard

Question

For the reaction 3A → 2B, the following graph is obtained experimentally. The rate of reaction when [A] = 0.2 M, is

Options

A.4 × 10−4 M min−1
B.(16/9) × 10−4 M min−1
C.1.6 × 10−3 M min−1
D.(16/3) ×10−3 M min−1

Solution

For given graph, 1 – n = –3 ⇒ n = 4 and –K(1 – n) = tan 45° ⇒ K(4 – 1) = 1

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