Mole ConceptHard
Question
In a textile mill, a double effect evaporator system concentrates weak liquor containing 4% (by mass) caustic soda to produce a lye containing 25% solids (by mass). What is the weight of water evaporated per 100 g feed in the evaporator?
Options
A.125.0 g
B.50.0 g
C.84.0 g
D.16.0 g
Solution
In 100 g of weak liquor, the mass of caustic soda present = 4 g. As on evaporation, only loss in mass of water will occur, the final mass of solid must be 4 g. If ‘x’ g water is evaporated, then
$(100 - x) \times \frac{25}{100} = 4 \Rightarrow x = 84$
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