Center of MassHard
Question
A uniform rod of mass m and length 2l lies on smooth horizontal surface. A particle of same mass m is connected to string of length l, whose other end is connected to rod. Initially string is taut and both rod and string lies in same horizontal plane with 90o angle between them. If particle is given initially velocity v0 perpendicular to string, then just after giving velocity v0 to particle :-
Options
A.linear acceleration of center of mass of rod will be 
B.angular acceleration of rod will be 
C.tension in string will be 
D.angular acceleration of rod will be 
Solution
T = MaC ......(i)
Tl =
α ......(ii)
T + M(aC + lα) =
......(iii)
from (i), (ii) and (iii)
ac =
α = 
Tc =
Tl =
α ......(ii)T + M(aC + lα) =
......(iii)from (i), (ii) and (iii)
ac =
α = Tc =
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