Center of MassHard
Question
A uniform rod of mass m and length 2l lies on smooth horizontal surface. A particle of same mass m is connected to string of length l, whose other end is connected to rod. Initially string is taut and both rod and string lies in same horizontal plane with 90o angle between them. If particle is given initially velocity v0 perpendicular to string, then just after giving velocity v0 to particle :-
Options
A.linear acceleration of center of mass of rod will be 
B.angular acceleration of rod will be 
C.tension in string will be 
D.angular acceleration of rod will be 
Solution
T = MaC ......(i)
Tl =
α ......(ii)
T + M(aC + lα) =
......(iii)
from (i), (ii) and (iii)
ac =
α = 
Tc =
Tl =
α ......(ii)T + M(aC + lα) =
......(iii)from (i), (ii) and (iii)
ac =
α = Tc =
Create a free account to view solution
View Solution FreeMore Center of Mass Questions
A ball of mass 50 gm is dropped from a height h = 10 m. It rebounds losing 75 percent of its kinetic energy. If it remai...A disc is placed on the surface of a pond which has refractive index 5/3. A source of light is placed 4m below the surfa...There are hundred identical sliders equally spaced on a frictionless track as shown in the figure. Initially all the sli...A mass of 0.2 kg moving with a speed of 2m/s strikes a horizontal spring and is brough to rest after compressing the spr...A bullet of mass m = 50 gm strikes (ᐃt ≈ 0)a sand bag of mass M = 5 kg hanging from a fixed point, with a ho...