Center of MassHard

Question

A super-ball is to bounce elastically back and forth between two rigid walls at a distance d from each other. Neglecting gravity and assuming the velocity of super-ball to be v0 horizontally, the average force being exerted by the super-ball on one wall is :

Options

A.
B.
C.
D.

Solution


t =   (time for succeesive collision )
N × t = dP = mv0 − (−mv0)
N × = 2mv0
∴ N = .

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