Atomic StructureHard
Question
In a hydrogen like atom in which every atom is in a particular excited state. Now a stream of photons of energy 
E0 bombarded into it and is absorbed by the hydrogen like atom and subsequently its emission spectrum shows 10 different lines in which some lines have energy less than E0 and some lines have energy more than E0 and some lines have energy equal to E0. (Where E0 is ionization energy of hydrogen atom in ground state).
E0 bombarded into it and is absorbed by the hydrogen like atom and subsequently its emission spectrum shows 10 different lines in which some lines have energy less than E0 and some lines have energy more than E0 and some lines have energy equal to E0. (Where E0 is ionization energy of hydrogen atom in ground state).Options
A.The final quantum no. of electron in the atom is 5
B.The initial quantum no. of electron in the atom is 3
C.Atomic no. of the atom is 2
D.None of these
Solution
As emission spectrum of the atom shows 10 different lines, so the highest excited state of the electron is n = 5.
As some lines have energy less then
E0 and some have more than E0 and some have equal toit. So initial state of electron can be n = 2 or n = 3.
Again if initial level is n = 2, then Z2
- Z2
E0, Z is in fraction (not possible)
If n = 3, then
Z2
- Z2
E0, Z = 2
As some lines have energy less then
E0 and some have more than E0 and some have equal toit. So initial state of electron can be n = 2 or n = 3.Again if initial level is n = 2, then Z2
- Z2E0, Z is in fraction (not possible)If n = 3, then
Z2
- Z2E0, Z = 2Create a free account to view solution
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