Math miscellaneousHard
Question
Number of solutions of the equation ex(ex - 2) = 5|ex - 1| - 7 is -
Options
A.0
B.1
C.2
D.4
Solution
Put ex - 1 = t
⇒ (t + 1) (t - 1) = 5|t| - 7
⇒ t2 - 5|t| + 6 = 0
⇒ ex - 1 = ± 2; ex - 1 = ± 3
⇒ ex = 3; ex = 4 only ∴ 2 solutions.
⇒ (t + 1) (t - 1) = 5|t| - 7
⇒ t2 - 5|t| + 6 = 0
⇒ ex - 1 = ± 2; ex - 1 = ± 3
⇒ ex = 3; ex = 4 only ∴ 2 solutions.
Create a free account to view solution
View Solution FreeMore Math miscellaneous Questions
If , are such that = 1, || and = √2, = √3, = , then the angle between & is...is equal to :...Suppose f(x) is differentiable x = 1 and f(1 + h) = 5, then f′(1) equals...If ϖ (≠ 1) is a cube root of unity, and (1 + ϖ)7 = A + B ϖ. Then (A, B) equals...The equation of the plane containing the line 2x − 5y + z = 3 ; x + y + 4z = 5, and parallel to the plane, x + 3y ...