Circular MotionHard

Question

A thin uniform rod of mass 5 kg and length 1m is held in horizontal position with the help of strings attached to ends of rod. Other ends of strings are held by some external agent. Now end A is pulled down with speed VA = 3t and end B is pulled down with speed VB = t, where t is time in sec. Choose the CORRECT choice (s) at time t = 0 :-
         

Options

A.Angular acceleration of rod is 2 rad/s2
B.Tension in left string is
C.Acceleration of rod is 1m/24
D.Tension in right string is

Solution

         
ac + α = al
ac - α = a2
⇒ α = = 2rad/s2
α = = 2m/s2
T1 + T2 - mg = mac
(T1 - T2) α
⇒ T1 = N and T2 = N

Create a free account to view solution

View Solution Free
Topic: Circular Motion·Practice all Circular Motion questions

More Circular Motion Questions

A point mass m is suspended from a light thread of length, fixed at O, is whirled in a horizontal circle at constant spe...On a train moving along east with a constant speed v, a boy revolves a bob with string of length on smooth surface of a ...A curved section of a road is banked for a speed v. If there is no friction between road and tyres of the car, then:...In the above question . is zero for:...A particle is going with constant speed along a uniform helical and spiral path separately as shown in figure...