Circular MotionHardBloom L3
Question
On a train moving along east with a constant speed v, a boy revolves a bob with string of length on smooth surface of a train, with equal constant speed v relative to train. Mark the correct option(s).
Options
A.Maximum speed of bob is 2 v in ground frame.
B.Tension in string connecting bob is $\frac{4mv^{2}}{\mathcal{l}}$ at an instant.
C.Tension in string is $\frac{mv^{2}}{\mathcal{l}}$ at all the moments.
D.Minimum speed of bob is zero in ground frame.
Solution
Sol. Circular motion is in train's frame. In this frame sped v is constant.
${\overrightarrow{v}}_{bob,ground} = {\overrightarrow{v}}_{b,T} + {\overrightarrow{v}}_{T}$
vmax = v + v = 2v
vmin = –v + v = 0
$T = \frac{mv^{2}}{\mathcal{l}}$
Create a free account to view solution
View Solution FreeMore Circular Motion Questions
Initial angular velocity of a circular disc of mass M is ω1. Then two small spheres of mass m are attached gently t...Two racing cars of masses m1 and m2 are moving in circles of radii r and 2r respectively ; their angular speeds are equa...A uniform circular disc of radius 50 cm at rest is free to tum about an axis which is perpendicular to its planeand pass...A car of mass m is moving on a level circular track of radius R. If μs represents the static frictionbetween the ro...A car is going on an overbridge of radius R, maintaining a constant speed. As the car is descending on the overbridge fr...