Set, Relation and FunctionHard
Question
The range of k for which the inequality k cos2x - k cos x + 1 ≥ 0 ∀ x ∈ R, is -
Options
A.k < 
B.k > 4
C.
≤ k ≤ 4
D.
≤ k ≤ 2
Solution
We have k cos2x - k cosx + 1 ≥ 0
⇒ k(cos2x - cos x) + 1 ≥ 0
cos2x - cos x = (cos x -
)2 - 
Since -
≤ cos2x - cos x ≤ 2
We have 2k + 1 ≥ 0 and -
+ 1 ≥ 0
⇒ -
≤ k ≤ 4
⇒ k(cos2x - cos x) + 1 ≥ 0
cos2x - cos x = (cos x -
Since -
We have 2k + 1 ≥ 0 and -
⇒ -
Create a free account to view solution
View Solution FreeMore Set, Relation and Function Questions
Let f: → be a function given by f(x) = max(sinx, tan2x). Identify the correct statement(s) -...Given the sets A = {1,2,3}, B = {3,4}, C = {4,5,6}, then is -...The set {x : x ∈ N, x is prime and 3 < x < 5} is-...If A, B and C are any three sets, then A × (B ∪ C) is -...If A, B, C are three sets, then A - (B ∪ C) is equal to :-...