Set, Relation and FunctionEasy
Question
Let A(h, k), B(1, 1) and C(2, 1) be the vertices of a right angled triangle with AC as its hypotenuse. If the area of the triangle is 1, then the set of values which ′k′ can take is given by
Options
A.{1, 3}
B.{0, 2}
C.{-1, 3}
D.{-3, -2}
Solution

× 1(k - 1) = ± 1K - 1 = ± 2
k = 3
k = - 1
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