Math miscellaneousEasy
Question
The number of solutions of equation x + y + z = 101 where x,y,z ∈ {0,1,2,.......50} will be -
Options
A.5253
B.4950
C.3927
D.1275
Solution
All non negative itnegral solution 103C2
Number of solutions in which x ≥ 51 will be
x′ + y + z = 50 → 3C2
3C152C2 undesirable solution should be rejected
103C2 - 3. 52C2 = 1275
Number of solutions in which x ≥ 51 will be
x′ + y + z = 50 → 3C2
3C152C2 undesirable solution should be rejected
103C2 - 3. 52C2 = 1275
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