Chemical BondingHard

Question

If x, y, z are in A.P. and tan-1x, tan-1y and tan-1z are also in A.P., then

Options

A.x = y = z
B.2x = 3y = 6z
C.6x = 3y = 2z
D.6x = 4y = 3z

Solution

2y = x + z
and 2tan-1y = tan-1x + tan-1z

⇒   y2 = zx
⇒   x = y = z

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