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Question

Find the magnetic dipole moment of the rectangular loop shown in the figure. Sides, a = 3m, b = 4m and c = 2m, current in the loop I = 1 Amp

Options

A.11.8 Am²

B.15.8 Am²

C.13.8 Am²

D.12.8 Am²

Solution

= Iab ĵ + Ibc cos 45^o (-ĵ) + I bc sin 45^o î
= 1 × 4 × 2 × + 1 × 12 ĵ - 8 ĵ = 4√2 î + 4(3 - √2)ĵ Am²
Magnitude μ = = 11.8 Am²

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