CapacitanceHard
Question
In the given circuit, with steady current, find the potential drop across the capacitor.
Options
A.V/4
B.V/2
C.V/3
D.V
Solution
In steady state no current will pass through the capacitor.
In the outer loop,
2V - 2iR - iR - V = 0
⇒ i = V/3R
For the upper loop, V - VC - iR - V = 0 ⇒ |VC| = iR = V/3
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