Area under the curveMedium

Question

If ′A′ denotes area of the region bounded by y = sin-1(x2), y = 0, x = 1 and x = -1, then -

Options

A.A = 2(1 - sin-1x2)dx
B.A = 2(1 - )dx
C.0 < A <
D. < A < π

Solution

       
A ≤ 2
A ≤
y sin-1 x2 ⇒ x =
∴ A = 2(1- )dy

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