Area under the curveHard
Question
The area (in square units) bounded by the curves y = √x, 2y - x + 3 = 0, x-axis and lying in the first quadrant is :
Options
A.9
B.36
C.18
D.

Solution

intersection point

⇒ x - 2√x - 3 = 0
√x = 3, - 1 ⇒ x = 9
Required Area
- area of ᐃ ABC
= 18 - 9 = 9
Create a free account to view solution
View Solution FreeMore Area under the curve Questions
If the curves y2 = 6x, 9x2 + by2 = 16 intersect each other at right angles, then the value of b is :...Let S be the area of the region enclosed by y = e-x2, y = 0, x = 0 and x = 1. Then...The area of the region for which 0 < y < 3 - 2x - x2 & x > 0 is -...The area between the curve y2 = 4x, y-axis, and y = − 1 and y = 3 is-...Area enclosed by the curve y = sin x between x = 2nπ to x = 2(n +1)π is -...