Math miscellaneousHard
Question
If a,b and c are in H.P and a,b and - 2c are in G.P., where a,b & c are non-zero, then -
Options
A.-2a,b and -2c are in A.P
B.
= 0
= 0C.- 2a,b and - 2c are in G.P
D.
= (a + b + c)2
= (a + b + c)2Solution
b =
and b2 = - 2ac
⇒ b =
⇒ a + b + c = 0
and b2 = - 2ac⇒ b =
⇒ a + b + c = 0Create a free account to view solution
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