The total length of potentiometer wire AB is 50 cm in the arrangement as shown in figure. If P is th

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The total length of potentiometer wire AB is 50 cm in the arrangement as shown in figure. If P is the point where the galvanometer shows zero reading then the length AP is $\_\_\_\_$ cm .

Accepted Answer

$\frac{6}{R_{AP}} = \frac{4}{R_{PB}}$;$$\begin{array}{r} \mathcal{l}_{AP} + \mathcal{l}_{PB} = 50\#(i) \ \frac{R_{AP}}{R_{PB}} = \frac{\mathcal{l}_{AP}}{\mathcal{l}_{PB}} = \frac{3}{2}\#(i) \end{array}$$$$\mathcal{l}_{AP} = \frac{3}{5} 	imes 50 = 30	ext{ }cm$$

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