Trigonometric EquationHard
Question
A curve which passes through origin and satisfies
(y + sinx . cos2(xy))sec2(xy)dx + (xsec2(xy) + siny)dy = 0 will be -
(y + sinx . cos2(xy))sec2(xy)dx + (xsec2(xy) + siny)dy = 0 will be -
Options
A.tan(xy)+2
=0
=0B.sin(2xy) + 2 = cos x + cos y
C.2 - sin(2xy) = cosx - cosy
D.sin(2xy) + 
= 0
= 0Solution
(y + sinx cos2xy)dx + (x + siny cos2(xy)dy = 0
ydx + xdy + cos2(xy)(sinx dx + sinydy) = 0
+ sin xdx + sin ydy = 0
sec2(xy)d(xy) + sinxdx + sinydy = 0
tan(xy) - cosx - cosy = C
and c = - 2 for y = (0) = 0
ydx + xdy + cos2(xy)(sinx dx + sinydy) = 0
+ sin xdx + sin ydy = 0sec2(xy)d(xy) + sinxdx + sinydy = 0
tan(xy) - cosx - cosy = C
and c = - 2 for y = (0) = 0
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