Coordination CompoundHard
Question
The ion which is not tetrahedral in shape is
Options
A.BF4-
B.NH4-
C.[Cu(NH3)4]2+
D.NiCl42+
Solution
In [Cu(NH3)4]2+ the hydridisation is dsp2Cu+2 = 3d94s0
When amonia approaches towerds the Cu+2 it is observed that the unpaired electron in the d-orbital gets exited to 4p-orbital resulting in dsp2 hybridisation.
The shape of dsp2 hydridisation is square planar.
When amonia approaches towerds the Cu+2 it is observed that the unpaired electron in the d-orbital gets exited to 4p-orbital resulting in dsp2 hybridisation.
The shape of dsp2 hydridisation is square planar.
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