Momentum and CollisionHard
Question
Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving withvelocity v along x-axis. After collision B has a velocity
in a direction perpendicular to the originaldirection. The mass A moves after collision in the direction
in a direction perpendicular to the originaldirection. The mass A moves after collision in the directionOptions
A.θ = tan-1 (- 1/2) to the x-axis
B.same as that of B
C.opposite to that of B
D.θ = tan-1 (1/2)to the x-axis
Solution
m1v1 cos θ = m2v .....(i)
m1v1 sin θ = m2v/2 .....(ii) Before collision
Divide : (ii) by (i) tan θ =
⇒ θ = tan-1
...............

m1v1 sin θ = m2v/2 .....(ii) Before collision
Divide : (ii) by (i) tan θ =
⇒ θ = tan-1
...............

Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
In determination of young modulus of elasticity of wire, a force is applied and extension is recorded. Initial length of...A vertical glass capillary tube, open at both ends, contains some water. Which of the following shapes may be taken by t...It is found that if a neutron suffers an elastic collinear collision with deuterium at rest, fractional loss of its en...A particle of mass M, starting from rest, undergoes uniform acceleration. If the speed accuired in time T is V, the powe...Find the center of mass (x,y,z) of the following stricture of four identical of four identical cubes if the length of ea...