Hard

Question

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

Options

A.θ = 45o
B.θ = tan-1
C.θ = tan-1(4)
D.θ = tan-1(2)

Solution


⇒ tan θ = 4 ⇒ θ = tan-1 (4)

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