KinematicsHard
Question
A bob of mass M is suspended by a massless string of length L. The horizontal velocity V at position A is just sufficient to make it reach the point B. The angle θ at which the speed of the bob is half of that at A, satisfies
Figure:
Figure:
Options
A.θ = 
B. < θ < 
< θ < C. < θ < 
< θ < D. < θ < π
< θ < πSolution
5mgl = m 
+ mgl(1 - cosθ)cos θ = -
Hence, 3π/4 < θ < π
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