Chemical Kinetics and Nuclear ChemistryMedium
Question
T50 of first - order rection is 10 min. Starting with 10 mol-1 rate after 20 min is
Options
A.0.0693 mol-1 min-1
B.0.0693 × 2.5 mol L-1 min-1
C.0.0693 × 5 mol L-2 min-1
D.0.0693 × 10 mol L-1 min-1
Solution
Initial concentration = 10 mol-1
∴ Conc. after 20 min(two half lives) = 2.5 mol-1
Now, k =
or 0.0693 min-1
∴ rate = k × [reactant]
= 0.0693 × 2.5 mol L-1 min-1
∴ Conc. after 20 min(two half lives) = 2.5 mol-1
Now, k =
or 0.0693 min-1
∴ rate = k × [reactant]
= 0.0693 × 2.5 mol L-1 min-1
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