Ionic EquilibriumHard
Question
In the manufacture of NH3 in Haber′s continuous flow process involving the reaction
H2(g) + 3H2(g)
2NH3(g) ᐃH = - 22.08 kcal. The favorable conditions are
H2(g) + 3H2(g)
2NH3(g) ᐃH = - 22.08 kcal. The favorable conditions areOptions
A.High pressure and low temperature due to low activation energy (Ea)
B.Low pressure and low temperature due to low Ea
C.High pressure and elevated optimum temperature due to high Ea
D.None of these
Solution
The reaction is exothermic and takes place with a decrease in number of molecules ofgaseous species. Obviously high pressure and low temperature are the favourable for theshift of equilibrium to products side. However, in continuous side. however in continuous side. However, in continuous flow process, optimum elevated flow prosess, optimum elevated temperature is required to have more NH3 due to high activation energy of the reaction.
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
An example of a reversible reaction is :...Which of the following when added to 1.0 L of 0.5 M HCl would result in maximum increase in pH :-...There exist an equilibrium between solid BaSO4, Ba2+ and SO42− ions in aqueous medium. Now, if equilibrium is disturbed ...Phenol on treatment with CO2 in the presence of NaOH followed by acidification produces compound X as the major product....At 25oC Kb for BOH = 1.0 × 10-12 . 0.01 M solution of BOH has [OH-]:...