NEET | 2018Ionic EquilibriumEasy

Question

The solubility of BaSO4 in water 2.42 × 103 gL–1 at 298 K. The value of solubility product (Ksp) will be
(Given molar mass of BaSO4 = 233 g mol–1)

Options

A.

(Given molar mass of BaSO4 = 233 g mol–1)

B.

1.08 × 10–12 mol2 L–2

C.

1.08 × 10–14 mol2 L–2

D.

1.08 × 10–8 mol2 L–2

Solution

solubility of BaSO4 = 2.42 × 10–3 gL–1
∴s =2.42×10-3233=1.038×10-5mol L-1ksp=S2=(1.038×10-5)2                =1.08×10-10 mol2 L-2
 

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