SHMMedium
Question
A 25 kg uniform solid sphere with a 20 cm radius is suspended by a vertical wire such that the point of suspension is vertically above the center of the sphere. A torque of 0.10 N-m is required to rotate the sphere through an angle of 1.0 rad and then maintain the orientation. If the sphere is then released, its time period of the oscillation will be :
Options
A.π sec
B.√2π sec
C.2π sec
D.4π sec
Solution
τ = - kθ
0.1 = - k(1.0), where k is torsional constant of the wire.
k =
T = 2π
= 2π
= 2π 
= 4π second
0.1 = - k(1.0), where k is torsional constant of the wire.
k =
T = 2π
= 2π = 2π = 4π secondCreate a free account to view solution
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