JEE Main | 2018Basic Maths and Units and DimensionsHard

Question

Unpolarized light of intensity I passes through an ideal polarizer A. Another identical polarizer B is placed behind A. The intensity of light beyond B is found to be 1/2. Now another identical polarizer C is placed between A and B. The intensity beyond B is now found to be I8. The angle between polarizer A and C is :

Options

A.

30o

B.

45o

C.

60o

D.

0o

Solution

Axis of transmission of A & B are parallel.

Now, 

I2cos4θ=I8⇒Cos4θ=14
cos θ=12
θ =45o

Create a free account to view solution

View Solution Free
Topic: Basic Maths and Units and Dimensions·Practice all Basic Maths and Units and Dimensions questions

More Basic Maths and Units and Dimensions Questions

Two identical straight wires are stretched so as to produce 6 beats/sec when vibrating simultaneously. On changing the t...A U tube with both ends open to the atmosphere, is partially filled with water. Oil, which is immiscible with water, is ...If the speed of the wave shown in the figure is 330 m/s in the given medium, then the equation of the wave propagating i...A disc is rolling (without slipping) on na horizontal surface. C is its center and Q and P are two points equidistant fr...When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the parti...