JEE Main | 2018Basic Maths and Units and DimensionsHard

Question

Unpolarized light of intensity I passes through an ideal polarizer A. Another identical polarizer B is placed behind A. The intensity of light beyond B is found to be 1/2. Now another identical polarizer C is placed between A and B. The intensity beyond B is now found to be I8. The angle between polarizer A and C is :

Options

A.

30o

B.

45o

C.

60o

D.

0o

Solution

Axis of transmission of A & B are parallel.

Now, 

I2cos4θ=I8⇒Cos4θ=14
cos θ=12
θ =45o

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