Sound WavesMedium
Question
When two tunning forks (fork 1 and forks2) are sounded simultaneously, 4 beats per second are heard. Now, some tape is attached on the prong of the fork 2. When the tuning forks are sounded again, 6 beats per second are heard If the original frequency of fork 1 is 200 Hz, then what was the original frequency of fork 2?
Options
A.200Hz
B.204Hz
C.194Hz
D.196Hz
Solution
Frequency of fork 1 = 200 Hz = n0
No, of beats heard when fork 2 is sounded with fork 1 = ᐃn = 4
Now we know that if loading (attaching tape) an unknown fork, the beat frequencyincreases (from 4 to 6 this case )then the frequency of the unknoen fork 2 is given by,
n = n0 - ᐃn = 200 - 4 = 196Hz
No, of beats heard when fork 2 is sounded with fork 1 = ᐃn = 4
Now we know that if loading (attaching tape) an unknown fork, the beat frequencyincreases (from 4 to 6 this case )then the frequency of the unknoen fork 2 is given by,
n = n0 - ᐃn = 200 - 4 = 196Hz
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