Sound WavesHard
Question
When two tunning forks (fork 1 and forks2) are sounded simultaneously, 4 beats per second are heard. Now, some tape is attached on the prong of the fork 2. When the tuning forks are sounded again, 6 beats per second are heard If the original frequency of fork 1 is 200 Hz, then what was the original frequency of fork 2?
Options
A.200Hz
B.204Hz
C.194Hz
D.196Hz
Solution
Frequency of fork 1 = 200 Hz = n0
No, of beats heard when fork 2 is sounded with fork 1 = ᐃn = 4
Now we know that if loading (attaching tape) an unknown fork, the beat frequencyincreases (from 4 to 6 this case )then the frequency of the unknoen fork 2 is given by,
n = n0 - ᐃn = 200 - 4 = 196Hz
No, of beats heard when fork 2 is sounded with fork 1 = ᐃn = 4
Now we know that if loading (attaching tape) an unknown fork, the beat frequencyincreases (from 4 to 6 this case )then the frequency of the unknoen fork 2 is given by,
n = n0 - ᐃn = 200 - 4 = 196Hz
Create a free account to view solution
View Solution FreeMore Sound Waves Questions
A sonometer wire resonates with a given tuning fork forming standing waves with five antinodes between the two bridge wh...If the time period of oscillation of mass m suspended from a spring is 2sec, the time period of mass 4m will be:...If in an experiment for determination of velocity of sound by resonance tube method using a tuning fork of 512 Hz, first...An open pipe is suddenly closed at one end with the result that the frequncy of third harmonic of the closed pipe is fou...A sound wave of frequency f travels is horizontally to the right. If it is reflected from a large vertical plane surface...