Sound WavesHard
Question
When two tunning forks (fork 1 and forks2) are sounded simultaneously, 4 beats per second are heard. Now, some tape is attached on the prong of the fork 2. When the tuning forks are sounded again, 6 beats per second are heard If the original frequency of fork 1 is 200 Hz, then what was the original frequency of fork 2?
Options
A.200Hz
B.204Hz
C.194Hz
D.196Hz
Solution
Frequency of fork 1 = 200 Hz = n0
No, of beats heard when fork 2 is sounded with fork 1 = ᐃn = 4
Now we know that if loading (attaching tape) an unknown fork, the beat frequencyincreases (from 4 to 6 this case )then the frequency of the unknoen fork 2 is given by,
n = n0 - ᐃn = 200 - 4 = 196Hz
No, of beats heard when fork 2 is sounded with fork 1 = ᐃn = 4
Now we know that if loading (attaching tape) an unknown fork, the beat frequencyincreases (from 4 to 6 this case )then the frequency of the unknoen fork 2 is given by,
n = n0 - ᐃn = 200 - 4 = 196Hz
Create a free account to view solution
View Solution FreeMore Sound Waves Questions
In arrangement given in figure if the block of mass m is displaced, the frequency is given by:...While measuring the speed of sound by performing a resonance column experiment, a student gets the first resonance condi...A boat at anchor is rocked by wave whose crests are 100m apart and velocity is 25 m/sec. The boat bounces up once in eve...Two pulse in a stretched string, whose centers are initially 8 cm apart, are moving towards each other as shown in the f...The equation of displacement of two waves are given as y1 = 10 sin (3πt + π/3) and y2 = 5 (sin 3πt + W...