ElectrochemistryEasy
Question
Through a solution of CuSO4 a current of 3 amperes was passed for 2 hours. At cathode 3 g of Cu2+ ions were discharged. The current efficiency is [At. wt. of Cu = 63.5]
Options
A.33.3%
B.42.2%
C.48.7%
D.54.4%
Solution
According to law of electrolysis, Mass deposited (m) - Z i t
or i =
Here, m = 3g, t = 2 t = 2 × 60 × 60 = 7200sec
Z =
; Eq. wt = 
∴ i =
= 1.266A
Efficiency of current
=
× 100
=
× 100 = 42.22%
or i =
Here, m = 3g, t = 2 t = 2 × 60 × 60 = 7200sec
Z =
; Eq. wt = ∴ i =
= 1.266A Efficiency of current
=
× 100=
× 100 = 42.22%Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
A current of 0.1A was passed for 2hr through a solution of cuprocyanide and 0.3745 g of copper was deposited on the cath...In a cell that utilises the reaction Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g) addition of H2SO4 to cathode compartment, ...The weight of silver (at. wt. = 108) displaced by a quantity of electricity which displaces 5600 mL of O2 at STP will be...For a electrochemical cell Zn|Zn2+ (C1 M)||Cu2+ (C2 M)|Cu, the decrease in free energy at a given temperature is a funct...Two electrochemical cells are assembled in which the following reactions occur:V2+ + VO2+ + 2H+ → 2V3+ + H2O; E°Cell = 0...