The configuration 42H > 73Ne > 94 Be shows :

Atomic number of the given element = 10 Electronic configuration = 1s2, 2s2 p6 1s2, 2s2 p6 1s2 ,2s2 2p6 is electronicconfiguration of Ne. 1s2, 2s22p6, 3s1 is excited oxidation state.

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Question

The configuration ⁴₂H > ⁷₃Ne > ⁹₄ Be shows :

Options

A.exicited state of O₂^-

B.excited state of neon atom

C.excited state of fluorine atom

D.ground state of fluorine atom

Solution

Atomic number of the given element = 10
Electronic configuration = 1s², 2s² p⁶ 1s², 2s² p⁶ 1s² ,2s² 2p⁶ is electronicconfiguration of Ne. 1s², 2s²2p⁶, 3s¹ is excited oxidation state.

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