Atomic StructureHard
Question
The configuration 42H > 73Ne > 94 Be shows :
Options
A.exicited state of O2-
B.excited state of neon atom
C.excited state of fluorine atom
D.ground state of fluorine atom
Solution
Atomic number of the given element = 10
Electronic configuration = 1s2, 2s2 p6 1s2, 2s2 p6 1s2 ,2s2 2p6 is electronicconfiguration of Ne. 1s2, 2s22p6, 3s1 is excited oxidation state.
Electronic configuration = 1s2, 2s2 p6 1s2, 2s2 p6 1s2 ,2s2 2p6 is electronicconfiguration of Ne. 1s2, 2s22p6, 3s1 is excited oxidation state.
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