Mole ConceptHard
Question
The reaction of calcium with water is represented by the equation
Ca + 2H2O → Ca(OH)2 + H2
What volume of H2 at STP woild be liberated when 8 gm of calcium completely reacts with water ?
Options
A.0.2cm3
B.0.4cm3
C.2240 cm3
D.4480 cm3
Solution
Ca + 2H2O → Ca(OH)2 + H2
According to the stoichiometry of reaction, 40 gm of Ca on complate reason with water librates = 2 gm H2
∴ 8gm of Ca. on complete reaction with water liberates =
× 8 gm H2
= 0.40 gm H2
=
× 22400 cm2
= 4480cm3 of H2 at S.T.P.
According to the stoichiometry of reaction, 40 gm of Ca on complate reason with water librates = 2 gm H2
∴ 8gm of Ca. on complete reaction with water liberates =
× 8 gm H2= 0.40 gm H2
=
× 22400 cm2= 4480cm3 of H2 at S.T.P.
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