AIPMT | 2014Nuclear Physics and RadioactivityHard
Question
A radio isotope X with a half life 1.4 × 109 years decays of Y which is stable. A sample of the rock from a cave was found to contain X and Y in the ratio 1 : 7.
The age of the rock is
The age of the rock is
Options
A.1.96 × 109 years
B.3.92 × 109 years
C.4.20 × 109 years
D.8.40 × 109 years
Solution
X : Y = 1 : 7
X : (X + Y) = 1 : 8 = 1 : 23
⇒ 3 half life
∴ ᐃT = 3 × 1.4 × 109 yrs = 4.2 × 109 yrs.
X : (X + Y) = 1 : 8 = 1 : 23
⇒ 3 half life
∴ ᐃT = 3 × 1.4 × 109 yrs = 4.2 × 109 yrs.
Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
A nucleus has mass number $\alpha$ and radius $R_{\alpha}$. Another nucleus has mass number $\beta$ and radius $R_{\beta...The amount of radioactive substance left after one hour whose half life is 20 minutes is :...The wave number of the series limit of lyman series is -...The activity of a radioactive sample is 9750 counts/min at t = 0 and 975 counts/min at t = 5 minute. The decay constant ...In the following reaction X is : -20Ca40 + X → 21Sc43 + 1H1...