Nuclear Physics and RadioactivityEasy
Question
Half-life of a radioactive substance is 20 minutes. Difference between points of time when it is 33% disintegrated and 67% disintegrated is approximately
Options
A.10 min
B.20 min
C.30 min
D.40 min
Solution
λ = 
= 0.03465]
Now time of decay t =
⇒ t1 =
= 11.6min
and t2 =
= 32 min
Thus time difference between points of time
= t1 - t2 = 32 - 11.6 = 20.4 min ≈ 20 min
= 0.03465]Now time of decay t =
⇒ t1 =
= 11.6minand t2 =
= 32 minThus time difference between points of time
= t1 - t2 = 32 - 11.6 = 20.4 min ≈ 20 min
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