AIPMT | 2014Photoelectric EffectHard
Question
The binding energy per nucleon of 
and 
nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction 
Li + 
H → 
He + He + Q, the value of energy Q released is
and nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction Li + H → He + He + Q, the value of energy Q released isOptions
A.19.6 MeV
B.-2.4 MeV
C.8.4 MeV
D.17.3 MeV
Solution
Q = 2(BE of He) - (BE of Li)
= 2 × (4 × 7.06) - (7 × 5.60)
= 56.48 - 39.2 = 17.3 MeV
= 2 × (4 × 7.06) - (7 × 5.60)
= 56.48 - 39.2 = 17.3 MeV
Create a free account to view solution
View Solution FreeMore Photoelectric Effect Questions
To increase the hardness of X-rays in coolidge tube we should -...For the structural analysis of crystals, X-rays are used because :...In the Davisson and Germer experiment, the velocity of electrons emitted from the electron gun can be increased by...The wavelength of the most energetic X-ray emitted when a metal target is bombarded by electrons having kinetic energy 1...The energy of the reaction Li1 + p 2 He4 is (the binding energy per nucleon in Li7 and He4 nuclei are 5.60 and 7.06 MeV ...