Photoelectric EffectHard
Question
Nuclei X decay into nuclei Y by emitting a particles. Energies of a particle are found to be only 1 MeV & 1.4 MeV. Disregarding the recoil of nuclei Y. The energy of γ photon emitted will be
Options
A.0.8 MeV
B.1.4 MeV
C.1 MeV
D.0.4 MeV
Solution
Energy of γ photon
= Difference in energies
of α particles = 0.4 MeV
= Difference in energies
of α particles = 0.4 MeV
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