Nuclear Physics and RadioactivityMedium
Question
Nuclei X decay into nuclei Y by emitting a particles. Energies of a particle are found to be only 1 MeV & 1.4 MeV. Disregarding the recoil of nuclei Y. The energy of γ photon emitted will be
Options
A.0.8 MeV
B.1.4 MeV
C.1 MeV
D.0.4 MeV
Solution
Energy of γ photon
= Difference in energies
of α particles = 0.4 MeV
= Difference in energies
of α particles = 0.4 MeV
Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
A nucleus of mass M + ᐃm at rest splitts into two different nuclei each of mass M/2. If speedof light is c then sp...The amount of U235 to be fissioned, to operate 10 kW nuclear reactor is (Approximately)...The activity of radio active material is :-...The capacity of Tarapur Atomic Power Station is 200 MW. The energy produced at this station in one day will be :-...Energy equivalent to 10gm of U235 is: -...