AIPMT | 2014CapacitanceHard
Question
Two thin dielectric slabs of dielectric constants K2 and K2 (K1 < K2) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field E between the plates with distance d as measured from plate P is correctly shown by


Options
A.

B.

C.

D.

Solution
Electric field inside parallel plate capacitor having charge Q at place where dielectric is absent = 
where dielectric is present =

where dielectric is present =

Create a free account to view solution
View Solution FreeMore Capacitance Questions
In the circuit shown in the figure, there are two parallel plate capacitors each of the capacitance C.The switch S1 is p...A parallel plate capacitor has a dielectric slab of dielectric constant K between its plates that covers 1/3 of the area...An air capacitor of capacity C = 10 μF is connected to a constant voltage battery of 12 V. Now the space between th...The combination of capacitors with C1 = 3μF, C2 = 4 μF and C3 = 2 μF is charged by connecting AB to a bat...The wires of two electric heaters are made up of same material and have same value. On combining them firstly in series ...