Alternating CurrentHard
Question
A coil has an inductance of 0.7 henry and is joined in series with a resistance of 220Ω. When the alternating emf of 220 V at 50 Hz is applied to it then the phase through which current lags behind the applied emf and the wattless component of current in the circuit will be respectively
Options
A.30o, 1A
B.45o, 0.5A
C.60o, 1.5A
D.none of these
Solution
L = 0.7H, R = 220Ω, E0 = 220V, v = 50Hz.
This is an L - Rcircuit
Phase difference,
tan φ =
XL = 2πvL = 2 × 
× 50 × 0.7 = 220Ω
=
= 1 or, φ = 45o
Wattless component of current
= I0 sin φ =
=
= 0.5A
This is an L - Rcircuit
Phase difference,
tan φ =
XL = 2πvL = 2 × × 50 × 0.7 = 220Ω =
= 1 or, φ = 45o Wattless component of current
= I0 sin φ =
=
= 0.5ACreate a free account to view solution
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