Alternating CurrentHard
Question
A 50 Hz a.c source of 20 volt is connected across Rand C as show in figure. The voltage across R is 12 volt. The voltage across C is :
Options
A.8 V
B.16 V
C.10 V
D.not possible to determine unless values of R and C are given
Solution
E2 = VR2 = 
= VR2 + VC2
[Phase different between VR & VC is 90o]
(20)2 = (12)2 + VC2
⇒ VC2 = 400 - 144 = 256
⇒ VC = 16
= VR2 + VC2[Phase different between VR & VC is 90o]
(20)2 = (12)2 + VC2
⇒ VC2 = 400 - 144 = 256
⇒ VC = 16
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