Alternating CurrentHard

Question

The voltage of an AC source varies with time according to the equation, V = 100 sin 100 π t cos 100 πt. Where t is in second and V is in volt. Then :

Options

A.the peak voltage of the source is 100 volt    
B.the peak voltage of the source is (100/√2) volt
C.the peak voltage of the source is 50 volt   
D.the frequency of the source is 50 Hz

Solution

V = 100 sin100π t cos 100π t
V = 50 sin 200 π t
here VO = 50      &    ω = 200π     f = 100 Hz

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