Alternating CurrentHard
Question
A capacitor of capacitance 2μF is connected in the tank circuit of an oscillator oscillating with a frequency of 1 kHz. If the current flowing in the circuit is 2 m A, the voltage across the capacitor will be :
Options
A.0.16 V
B.0.32 V
C.79.5 V
D.159 V
Solution
Here, oscillating frequency
= 1kHz = 103 Hz
Reactance of capacitor =
Potential over capacitance
× i = 
× 2 × 10-3 = 
= 0.16 V
= 1kHz = 103 Hz
Reactance of capacitor =
Potential over capacitance
× i = × 2 × 10-3 = = 0.16 VCreate a free account to view solution
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