Alternating CurrentEasy
Question
A capacitor of capacity C is connected in A.C. circuit. The applied emf is V = V0 sinωt, then the current is :
Options
A.I = 
sinωt
sinωtB.I = sin(ωt + π/2)
sin(ωt + π/2)C.I = V0 ωC sinωt
D.I = V0 ωC sin (ωt + π/2)
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