MagnetismHard
Question
Electron moves at right angles to a magnetic field of 1.5 × 10-2 tesla with speed of 6 × 107 m/s. If the specific cahrge of the electron is 1.7 × 1011 C/kg. The radius of circular path will be
Options
A.3.31 cm
B.4.31 cm
C.1.31 cm
D.2.35 cm
Solution
B = 1.5 × 10-2 T
θ = 90o, sin θ = 1, v = 6 × 107 m/s
= 1.4 × 1011 C/kg
r =
= 2.35 × 10-2 m = 2.35cm
θ = 90o, sin θ = 1, v = 6 × 107 m/s
= 1.4 × 1011 C/kg r =
= 2.35 × 10-2 m = 2.35cm
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