Current Electricity and Electrical InstrumentHard
Question
The temperature of the cold junction of a thermocouple is 0oC and the temperature of the hot junction is ToC. The relation for the thermo emf is given by; E = AT - 
BT2
(when A = 16 and B = 0.08). The temprature of inversion will be:
BT2 (when A = 16 and B = 0.08). The temprature of inversion will be:
Options
A.500oC
B.460oC
C.600oC
D.400oC
Solution
Since, E = AT - BT2
E = 16T - 0.08T2 = 16T - 0.04T2
At temperature of inversion, E = 0
So, 16T - 0.04T2 = 0 ⇒ T = 0
or16 - 0.04T = 0
T =
400oC
BT2E = 16T -
0.08T2 = 16T - 0.04T2At temperature of inversion, E = 0
So, 16T - 0.04T2 = 0 ⇒ T = 0
or16 - 0.04T = 0
T =
400oCCreate a free account to view solution
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