Current Electricity and Electrical InstrumentHard
Question
An electrolyte bulb marked 40 W and 200 V, is used in a circuit of supply voltage 100V. Now its power is
Options
A.10 W
B.20 W
C.40 W
D.100 W
Solution
Resistance of bulb
= 1000 Ω
New power =
= 10 W.
= 1000 ΩNew power =
= 10 W.Create a free account to view solution
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