Current Electricity and Electrical InstrumentHard
Question
An electrolyte bulb marked 40 W and 200 V, is used in a circuit of supply voltage 100V. Now its power is
Options
A.10 W
B.20 W
C.40 W
D.100 W
Solution
Resistance of bulb
= 1000 Ω
New power =
= 10 W.
= 1000 ΩNew power =
= 10 W.Create a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
The supply voltage to a room is 120V. The resistance of the lead wires is 6Ω. A 60 W bulb is already switched on. W...Four resistances are connected in a circuit as shown in the following diagram.The value of the current in ampere in 4 oh...In the potentiometer, when the cell in the secondary circuit is shunted with $4\Omega$ resistance, the balance is obtain...Two cells of unequal emfs e1 and e2, and internal resistances r1 and r2 are joined as shown. VA and VB are the potential...Two resistance wires on joining in parallel the resultant resistance is ohm. One of the wire breaks, the effective resis...