ThermodynamicsHard
Question
The change in the entropy of a an ideal gas which went through an isothermal process from an initial state (P1, V1, T) to the final state (P2, V2, T) is equal to
Options
A.zero
B.R ln T
C.R ln 
D.R ln 
Solution
Workdone by n moles of a gas when its volume changes from V1 to V2 is,
W = nRT loge
For an isothermal process, ᐃU = 0
∴ ᐃQ = DU + W = 0 + RTln
∴ Entropy =
= RT ln 
W = nRT loge
For an isothermal process, ᐃU = 0
∴ ᐃQ = DU + W = 0 + RTln
∴ Entropy =
= RT ln Create a free account to view solution
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