ThermodynamicsHard
Question
Let 
and vp respectvely denote the mean speed, root mean squre speed and most monoatomic gas at absolute temperture t. The mass of the molecule is m. Then
and vp respectvely denote the mean speed, root mean squre speed and most monoatomic gas at absolute temperture t. The mass of the molecule is m. ThenOptions
A.no molecule can have a speed greater than (√2vrms)
B.no molecule can have a speed less than 
C.
< vp < Vrms
< vp < Vrms D.The average kinetic A and B with frictionaless is 
(mvp2)
(mvp2)Solution
vrms = 
and vp =
From these expressions, we can see that vp <
< vrms
Again, vrms = vp
and average kinetic energy of a gas molecule Ek =
mv2rms
and vp =
From these expressions, we can see that vp <
< vrmsAgain, vrms = vp
and average kinetic energy of a gas molecule Ek =
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