ThermodynamicsMedium
Question
The volume of a gas is reced adiabatically to (1/4) of its volume at 27oC. If γ = 1.4.The new temrereacture will be :
Options
A.300 × (4)0.4 K
B.150 × (4)0.4 K
C.250 × (4)0.4 K
D.none of these
Solution
For adiabatic change, The equation is TVγ-1 = constant
T1V1γ-1 = T2V2γ-1
(27 + 273) V2γ-1 = T2
300 × V1γ-1 =
⇒ T2 = 300 × 4γ-1
T2 = 300 × 41.4-1 = 300 × 40.4 K
T1V1γ-1 = T2V2γ-1
(27 + 273) V2γ-1 = T2
300 × V1γ-1 =
⇒ T2 = 300 × 4γ-1 T2 = 300 × 41.4-1 = 300 × 40.4 K
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